Difference between revisions of "1963 TMTA High School Algebra I Contest Problem 33"
Coolmath34 (talk | contribs) (Created page with "== Problem == From the formula <math>A=\frac{1}{2} H(B+C),</math> the value of <math>B</math> in terms of <math>A, H,</math> and <math>C</math> is: <math>\text{(A)} \quad \fr...") |
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<math>\text{(D)} \quad \frac{HC-2A}{H} \quad \text{(E)} \quad H-2A+C</math> | <math>\text{(D)} \quad \frac{HC-2A}{H} \quad \text{(E)} \quad H-2A+C</math> | ||
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== Solution == | == Solution == | ||
Isolate <math>B</math> step by step. | Isolate <math>B</math> step by step. | ||
Latest revision as of 10:56, 2 February 2021
Problem
From the formula 
the value of 
in terms of 
and 
is:
Solution
Isolate step by step.
![\[2A = H(B+C)\]](http://latex.artofproblemsolving.com/0/a/b/0ab973d47103cff8d288470aa3b36ef1c127f10f.png)
![\[2A = HB+HC\]](http://latex.artofproblemsolving.com/5/3/3/5335aedcdd7b76d97361961d7939fbc3f7f89328.png)
![\[2A-HC = HB\]](http://latex.artofproblemsolving.com/c/a/3/ca3231c8bc8bbcc5ee379c478b8382819322ee9e.png)
![\[\frac{2A-HC}{H} = B\]](http://latex.artofproblemsolving.com/4/1/6/416fc5a4a2fe00483830b909e3d78975fb5026ca.png)
The answer is 
See Also
| 1963 TMTA High School Mathematics Contests (Problems) | ||
| Preceded by Problem 32 |
TMTA High School Mathematics Contest Past Problems/Solutions | Followed by Problem 34 |
