Difference between revisions of "2021 JMPSC Accuracy Problems/Problem 13"
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Case 1: <math>x+y=4,3</math>. | Case 1: <math>x+y=4,3</math>. | ||
There are no possible answer when <math>x+y=3</math>, but when <math>x+y=4</math>, <math>x</math> can equal <math>3</math> or <math>1</math>. | There are no possible answer when <math>x+y=3</math>, but when <math>x+y=4</math>, <math>x</math> can equal <math>3</math> or <math>1</math>. |
Revision as of 23:19, 10 July 2021
Problem
Let and
be nonnegative integers such that
Find the sum of all possible values of
Solution
asdf
Case 1: .
There are no possible answer when
, but when
,
can equal
or
.
Case 2:
This works when
.
Therefore, the answer is
. ~ kante314