Art of Problem Solving
AoPS Online
Math texts, online classes, and more
for students in grades 5-12.
Visit AoPS Online ‚
Books for Grades 5-12 Online Courses
Beast Academy
Engaging math books and online learning
for students ages 6-13.
Visit Beast Academy ‚
Books for Ages 6-13 Beast Academy Online
AoPS Academy
Small live classes for advanced math
and language arts learners in grades 2-12.
Visit AoPS Academy ‚
Find a Physical Campus Visit the Virtual Campus

Difference between revisions of "2021 Fall AMC 10A Problems/Problem 2"
(→‎Solution)
Line 7: Line 7:
 
== Solution ==
 
== Solution ==
 
If Menkara instead shortens the length of the other side by <math>1</math> inch, then the dimensions of the index card will be <math>4\times5,</math> with area <math>\boxed{\textbf{(E) } 20}.</math>
 
If Menkara instead shortens the length of the other side by <math>1</math> inch, then the dimensions of the index card will be <math>4\times5,</math> with area <math>\boxed{\textbf{(E) } 20}.</math>
 +
 +
~MRENTHUSIASM

Revision as of 18:00, 22 November 2021

Problem

Menkara has a $4 \times 6$ index card. If she shortens the length of one side of this card by $1$ inch, the card would have area $18$ square inches. What would the area of the card be in square inches if instead she shortens the length of the other side by $1$ inch?

$\textbf{(A) } 16 \qquad\textbf{(B) } 17 \qquad\textbf{(C) } 18 \qquad\textbf{(D) } 19 \qquad\textbf{(E) } 20$

Solution

If Menkara instead shortens the length of the other side by $1$ inch, then the dimensions of the index card will be $4\times5,$ with area $\boxed{\textbf{(E) } 20}.$

~MRENTHUSIASM

Retrieved from "https://artofproblemsolving.com/wiki/index.php?title=2021_Fall_AMC_10A_Problems/Problem_2&oldid=165046"