Difference between revisions of "2021 Fall AMC 10A Problems/Problem 5"

Latest revision as of 19:12, 23 November 2021

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-Solution:
+#REDIRECT [[2021_Fall_AMC_12A_Problems/Problem_4]]
-By divisibility rules, when <math>A=1,</math> the number <math>202101</math> is divisible by <math>3.</math> When <math>A=3,</math> the number <math>202103</math> is divisible by <math>11.</math> When <math>A=5,</math> the number <math>202105</math> is divisible by <math>5.</math> When <math>A=7,</math> the number <math>202107</math> is divisible by <math>3.</math> Thus, by the process of elimination we have that the answer is <math>\boxed{\textbf{(E)}.}</math>
-~NH14