Difference between revisions of "Talk:2013 AIME I Problems/Problem 14"
| Line 1: | Line 1: | ||
| − | For solution 1 where they talk about <math>P \sin \theta + Q \cos \theta = \cos \theta - \dfrac{1}{4} \cos \theta - \dfrac{1}{8} \sin{2 \theta} - \dfrac{1}{16} \cos{3 \theta} + \cdots</math>, I got <cmath> \cos \theta - \frac{1}{4} \cos \theta + \frac{1}{8} \sin 2 \theta | + | For solution 1 where they talk about <math>P \sin \theta + Q \cos \theta = \cos \theta - \dfrac{1}{4} \cos \theta - \dfrac{1}{8} \sin{2 \theta} - \dfrac{1}{16} \cos{3 \theta} + \cdots</math>, I got <cmath> \cos \theta - \frac{1}{4} \cos \theta + \frac{1}{8} \sin 2 \theta + \frac{1}{16} \cos 3 \theta - \frac{1}{32} \sin 4 \theta + \dots </cmath> instead (the same as in solution 2), which is not what the solution 1 got. If the writer of solution 1 could resolve this, that would be great. |
~MeepMurp5 | ~MeepMurp5 | ||
Revision as of 12:16, 27 December 2021
For solution 1 where they talk about 
, I got ![\[\cos \theta - \frac{1}{4} \cos \theta + \frac{1}{8} \sin 2 \theta + \frac{1}{16} \cos 3 \theta - \frac{1}{32} \sin 4 \theta + \dots\]](http://latex.artofproblemsolving.com/5/4/b/54b9956eabb28d586c571b9165d978530cc379b0.png)
instead (the same as in solution 2), which is not what the solution 1 got. If the writer of solution 1 could resolve this, that would be great.
~MeepMurp5
