Difference between revisions of "G285 MC10B Problems/Problem 1"
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+ | ==Problem== | ||
+ | Find <math>\left \lceil {\frac{3!+4!+5!+6!}{2+3+4+5+6}} \right \rceil</math> | ||
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+ | <math>\textbf{(A)}\ 42\qquad\textbf{(B)}\ 43\qquad\textbf{(C)}\ 44\qquad\textbf{(D)}\ 45\qquad\textbf{(E)}\ 46</math> | ||
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==Solution== | ==Solution== | ||
− | + | We have <cmath>\frac{6+24+120+720}{20} = \frac{87}{2} = \lceil 43.5 \rceil \implies \boxed{\textbf{(C)}\ 44}</cmath> | |
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Latest revision as of 22:57, 3 June 2022
Problem
Find
Solution
We have