Difference between revisions of "2021 Fall AMC 10B Problems/Problem 16"

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~kingofpineapplz
 
~kingofpineapplz
==Video Solution==
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==Video Solution by Interstigation==
 
https://www.youtube.com/watch?v=0FtXvjn_4y0
 
https://www.youtube.com/watch?v=0FtXvjn_4y0
  

Revision as of 01:22, 9 June 2022

Problem

Five balls are arranged around a circle. Chris chooses two adjacent balls at random and interchanges them. Then Silva does the same, with her choice of adjacent balls to interchange being independent of Chris's. What is the expected number of balls that occupy their original positions after these two successive transpositions?

$(\textbf{A})\: 1.6\qquad(\textbf{B}) \: 1.8\qquad(\textbf{C}) \: 2.0\qquad(\textbf{D}) \: 2.2\qquad(\textbf{E}) \: 2.4$

Solution 1

After the first swap, we do casework on the next swap.


Case 1: Silva swaps the two balls that were just swapped

There is only one way for Silva to do this, and it leaves 5 balls occupying their original position.


Case 2: Silva swaps one ball that has just been swapped with one that hasn't swapped

There are two ways for Silva to do this, and it leaves 2 balls occupying their original positions.


Case 3: Silva swaps two balls that have not been swapped

There are two ways for Silva to do this, and it leaves 1 balls occupying their original positions.


Our answer is the average of all 5 possible swaps, so we get \[\frac{5+2\cdot2+2\cdot1}{5}=\frac{11}5=\boxed{(\textbf{D}) \: 2.2}.\]


~kingofpineapplz

Video Solution by Interstigation

https://www.youtube.com/watch?v=0FtXvjn_4y0

~Interstigation

See Also

2021 Fall AMC 10B (ProblemsAnswer KeyResources)
Preceded by
Problem 15
Followed by
Problem 17
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25
All AMC 10 Problems and Solutions

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