Difference between revisions of "Steve has one quarter, two nickels and three pennies. Assuming no items are free, for how many different-priced items could Steve individually pay for with exact change?"

(Created page with "Steve can use no quarters or one quarter, for two possibilities. Steve can use 0, 1, or 2 nickels, for three possibilities. And Steve can use 0, 1, 2, or 3 pennies, for four...")
(No difference)

Revision as of 17:33, 12 June 2022

Steve can use no quarters or one quarter, for two possibilities.

Steve can use 0, 1, or 2 nickels, for three possibilities.

And Steve can use 0, 1, 2, or 3 pennies, for four possibilities. That gives $2 \cdot 3 \cdot 4 = 24$ possible combinations. But we must remove the combination where Steve does not use any coins, leaving us with $24 - 1 = \boxed{23}.$