Difference between revisions of "2000 AMC 12 Problems/Problem 3"
m |
(→Solution) |
||
| Line 5: | Line 5: | ||
== Solution == | == Solution == | ||
| − | Since Jenny eats <math>20%</math> of her jelly beans per day, <math>80%=\frac{4}{5}</math> of her jelly beans remain after one day. | + | Since Jenny eats <math>20\%</math> of her jelly beans per day, <math>80\%=\frac{4}{5}</math> of her jelly beans remain after one day. |
Let <math>x</math> be the number of jelly beans in the jar originally. | Let <math>x</math> be the number of jelly beans in the jar originally. | ||
| Line 13: | Line 13: | ||
<math>\frac{16}{25}\cdot x=32</math> | <math>\frac{16}{25}\cdot x=32</math> | ||
| − | <math> | + | <math>x=\frac{25}{16}\cdot32= 50 \Rightarrow B </math> |
== See also == | == See also == | ||
Revision as of 13:20, 17 October 2007
Problem
Each day, Jenny ate $20%$ (Error compiling LaTeX. Unknown error_msg) of the jellybeans that were in her jar at the beginning of that day. At the end of the second day, 
remained. How many jellybeans were in the jar originally?
Solution
Since Jenny eats 
of her jelly beans per day, 
of her jelly beans remain after one day.
Let 
be the number of jelly beans in the jar originally.
