Difference between revisions of "Simson line"
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<math>ACBP</math> is cyclis as desired. | <math>ACBP</math> is cyclis as desired. | ||
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+ | '''vladimir.shelomovskii@gmail.com, vvsss''' | ||
+ | |||
+ | ==Simson line of a complete quadrilateral== | ||
+ | Let four lines made four triangles of a complete quadrilateral. In the diagram these are <math>\triangle ABC, \triangle ADE, \triangle CEF, \triangle BDF.</math> | ||
+ | Let <math>M</math> be the Miquel point of a complete quadrilateral. Let <math>D, E, F,</math> and <math>G</math> be the foots of the perpendiculars dropped from <math>M</math> to lines <math>AB, AC, BC,</math> and EF, respectively. | ||
+ | |||
+ | Prove that points <math>D, E, F,</math> and <math>G</math> are collinear. | ||
+ | |||
+ | |||
+ | <i><b>Proof</b></i> | ||
+ | |||
+ | *[[Miquel point]] | ||
'''vladimir.shelomovskii@gmail.com, vvsss''' | '''vladimir.shelomovskii@gmail.com, vvsss''' |
Revision as of 12:26, 7 December 2022
In geometry, given a triangle ABC and a point P on its circumcircle, the three closest points to P on lines AB, AC, and BC are collinear.
Simson line (main)
Let a triangle and a point
be given.
Let and
be the foots of the perpendiculars dropped from P to lines AB, AC, and BC, respectively.
Then points and
are collinear iff the point
lies on circumcircle of
Proof
Let the point be on the circumcircle of
is cyclic
is cyclic
is cyclic
and
are collinear as desired.
Proof
Let the points and
be collinear.
is cyclic
is cyclic
is cyclis as desired.
vladimir.shelomovskii@gmail.com, vvsss
Simson line of a complete quadrilateral
Let four lines made four triangles of a complete quadrilateral. In the diagram these are
Let
be the Miquel point of a complete quadrilateral. Let
and
be the foots of the perpendiculars dropped from
to lines
and EF, respectively.
Prove that points and
are collinear.
Proof
vladimir.shelomovskii@gmail.com, vvsss
Problem
Let the points and
be collinear and the point
Let and
be the circumcenters of triangles
and
Prove that lies on circumcircle of
Proof
Let and
be the midpoints of segments
and
respectively.
Then points and
are collinear
is Simson line of
lies on circumcircle of
as desired.
vladimir.shelomovskii@gmail.com, vvsss