Difference between revisions of "1985 AJHSME Problems/Problem 13"
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Their total is <math>3\text{ miles}+5\text{ miles}=8\text{ miles}</math>, which is <math>\boxed{\text{B}}</math> | Their total is <math>3\text{ miles}+5\text{ miles}=8\text{ miles}</math>, which is <math>\boxed{\text{B}}</math> | ||
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| + | ==Video Solution== | ||
| + | https://youtu.be/LOluquXpZ6A | ||
| + | |||
| + | ~savannahsolver | ||
==See Also== | ==See Also== | ||
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{{AJHSME box|year=1985|num-b=12|num-a=14}} | {{AJHSME box|year=1985|num-b=12|num-a=14}} | ||
[[Category:Introductory Algebra Problems]] | [[Category:Introductory Algebra Problems]] | ||
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| + | {{MAA Notice}} | ||
Latest revision as of 07:13, 13 January 2023
Contents
Problem
If you walk for 
minutes at a rate of 
and then run for 
minutes at a rate of 
, how many miles will you have gone at the end of one hour and 
minutes?
Solution
minutes is 
of an hour, so the walking contributes 
.
Similarly, minutes is 
of an hour, so the running adds 
.
Their total is 
, which is 
Video Solution
~savannahsolver
See Also
| 1985 AJHSME (Problems • Answer Key • Resources) | ||
| Preceded by Problem 12 |
Followed by Problem 14 | |
| 1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 | ||
| All AJHSME/AMC 8 Problems and Solutions | ||
The problems on this page are copyrighted by the Mathematical Association of America's American Mathematics Competitions. 
