Difference between revisions of "2023 AMC 8 Problems/Problem 19"
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− | == | + | ==Solution 1== |
By AA~ similarity triangle we can find the ratio of the area of big: small —> <math>\frac{9}{4}</math> then there are a relative <math>5</math> for the <math>3</math> trapezoids combines. For <math>1</math> trapezoid it is a relative <math>53</math> so now the ratio is <math>\frac{5}{\frac{3}{4}}</math> which can simplify to <math>\boxed{\text(C) \frac{5}{12}}</math> | By AA~ similarity triangle we can find the ratio of the area of big: small —> <math>\frac{9}{4}</math> then there are a relative <math>5</math> for the <math>3</math> trapezoids combines. For <math>1</math> trapezoid it is a relative <math>53</math> so now the ratio is <math>\frac{5}{\frac{3}{4}}</math> which can simplify to <math>\boxed{\text(C) \frac{5}{12}}</math> | ||
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~apex304, SohumUttamchandani, wuwang2002, TaeKim, Cxrupptedpat | ~apex304, SohumUttamchandani, wuwang2002, TaeKim, Cxrupptedpat | ||
+ | ==Solution 2== | ||
+ | Subtracting the larger equilateral triangle from the smaller one yields the sum of the three trapezoids. Since the ratio of the side lengths of the larger to the smaller one is <math>3:2</math>, we can set the side lengths as <math>3</math> and <math>2</math>, respectively. So, the sum of the trapezoids is <math>\frac{9\sqrt{3}}{4}-\frac{4\sqrt{3}}{4}=\frac{5}{4}\sqrt{3}. We are also told that the three trapezoids are congruent, thus the area of each of them is </math>\frac{1}{3} \cdot \frac{5}{4}\sqrt{3}=\frac{5}{12}\sqrt{3}<math>. Hence, the area is \frac{\frac{5}{12}\sqrt{3}}{\sqrt{3}}=\boxed{\text(C)\ \frac{5}{12}}</math>. | ||
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+ | ~MrThinker | ||
==Video Solution by OmegaLearn (Using Similar Triangles)== | ==Video Solution by OmegaLearn (Using Similar Triangles)== |
Revision as of 21:08, 24 January 2023
Contents
[hide]Solution 1
By AA~ similarity triangle we can find the ratio of the area of big: small —> then there are a relative for the trapezoids combines. For trapezoid it is a relative so now the ratio is which can simplify to
~apex304, SohumUttamchandani, wuwang2002, TaeKim, Cxrupptedpat
Solution 2
Subtracting the larger equilateral triangle from the smaller one yields the sum of the three trapezoids. Since the ratio of the side lengths of the larger to the smaller one is , we can set the side lengths as and , respectively. So, the sum of the trapezoids is \frac{1}{3} \cdot \frac{5}{4}\sqrt{3}=\frac{5}{12}\sqrt{3}.
~MrThinker
Video Solution by OmegaLearn (Using Similar Triangles)
Animated Video Solution
~Star League (https://starleague.us)