Difference between revisions of "1985 AJHSME Problems/Problem 1"
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By the [[associative property]], we can rearrange the numbers in the numerator and the denominator. <cmath>\frac{3}{3}\cdot \frac{5}{5}\cdot\frac{7}{7}\cdot\frac{9}{9}\cdot\frac{11}{11}=1\cdot1\cdot1\cdot1\cdot1=\boxed{\text{(A)} 1}</cmath> | By the [[associative property]], we can rearrange the numbers in the numerator and the denominator. <cmath>\frac{3}{3}\cdot \frac{5}{5}\cdot\frac{7}{7}\cdot\frac{9}{9}\cdot\frac{11}{11}=1\cdot1\cdot1\cdot1\cdot1=\boxed{\text{(A)} 1}</cmath> | ||
− | ==Solution 2 | + | ==Solution 2 == |
Multlipication gives:<cmath>\frac{15}{99}\cdot\frac{693}{105}=\frac{10395}{10395}=\boxed{\text{(A)}\ 1}.</cmath> | Multlipication gives:<cmath>\frac{15}{99}\cdot\frac{693}{105}=\frac{10395}{10395}=\boxed{\text{(A)}\ 1}.</cmath> | ||
Revision as of 20:52, 26 March 2023
Contents
[hide]Problem
Solution 1
By the associative property, we can rearrange the numbers in the numerator and the denominator.
Solution 2
Multlipication gives:
See Also
1985 AJHSME (Problems • Answer Key • Resources) | ||
Preceded by First Question |
Followed by Problem 2 | |
1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 | ||
All AJHSME/AMC 8 Problems and Solutions |
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