Difference between revisions of "1985 AJHSME Problems/Problem 4"
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+ | ~savannahsolver | ||
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Latest revision as of 10:52, 24 June 2023
Contents
Problem
The area of polygon , in square units, is
Solution 1
Obviously, there are no formulas to find the area of such a messed up shape, but we do recognize some shapes we do know how to find the area of.
If we continue segment until it reaches the right side at
, we create two rectangles - one on the top and one on the bottom.
We know how to find the area of a rectangle, and we're given the sides! We can easily find that the area of is
. For the rectangle on the bottom, we do know the length of one of its sides, but we don't know the other.
Note that , and
, so we must have
The area of the bottom rectangle is then
Finally, we just add the areas of the rectangles together to get .
Solution 2
Let be the area of polygon
. Also, let
be the intersection of
and
when both are extended.
Clearly,
Since and
,
.
To compute the area of , note that
We know that ,
,
, and
, so
Thus
Finally, we have
This is answer choice
Video Solution by BoundlessBrain!
Video Solution
~savannahsolver
See Also
1985 AJHSME (Problems • Answer Key • Resources) | ||
Preceded by Problem 3 |
Followed by Problem 5 | |
1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 | ||
All AJHSME/AMC 8 Problems and Solutions |
The problems on this page are copyrighted by the Mathematical Association of America's American Mathematics Competitions.