Difference between revisions of "2023 AMC 10B Problems/Problem 17"

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The answers will be uploaded soon
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== Solution ==
- MRP
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<asy>
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import geometry;
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pair A = (-3, 4);
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pair B = (-3, 5);
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pair C = (-1, 4);
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pair D = (-1, 5);
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pair AA = (0, 0);
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pair BB = (0, 1);
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pair CC = (2, 0);
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pair DD = (2, 1);
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draw(D--AA,dashed);
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draw(A--B);
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draw(A--C);
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draw(B--D);
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draw(C--D);
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draw(A--AA);
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draw(B--BB);
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draw(C--CC);
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draw(D--DD);
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// Dotted vertices
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dot(A); dot(B); dot(C); dot(D);
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dot(AA); dot(BB); dot(CC); dot(DD);
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draw(AA--BB);
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draw(AA--CC);
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draw(BB--DD);
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draw(CC--DD);
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</asy>
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The diagonal of the box is
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<cmath>\begin{align*}
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  \sqrt{a^+b^2+c^2}&=
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\end{align*}
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</cmath>
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~Technodoggo

Revision as of 15:06, 15 November 2023

Solution

[asy] import geometry; pair A = (-3, 4); pair B = (-3, 5); pair C = (-1, 4); pair D = (-1, 5);   pair AA = (0, 0); pair BB = (0, 1); pair CC = (2, 0); pair DD = (2, 1);     draw(D--AA,dashed);  draw(A--B); draw(A--C); draw(B--D); draw(C--D);  draw(A--AA); draw(B--BB); draw(C--CC); draw(D--DD);  // Dotted vertices dot(A); dot(B); dot(C); dot(D);    dot(AA); dot(BB); dot(CC); dot(DD);  draw(AA--BB); draw(AA--CC); draw(BB--DD); draw(CC--DD);  [/asy]

The diagonal of the box is

\begin{align*}    \sqrt{a^+b^2+c^2}&= \end{align*}

~Technodoggo