Difference between revisions of "1987 OIM Problems/Problem 6"

(Created page with "== Problem == Let <math>ABCD</math> be a planar convex quadrilateral, <math>P</math> and <math>QQ</math> are points of <math>AD</math> and <math>BC</math> respectively such th...")
 
 
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<cmath>\frac{AP}{PD}=\frac{AB}{DC}=\frac{BQ}{QC}</cmath>
 
<cmath>\frac{AP}{PD}=\frac{AB}{DC}=\frac{BQ}{QC}</cmath>
 
Prove that the angles that are formed between line <math>PQ</math> and lines <math>AB</math> and <math>DC</math> are equal.
 
Prove that the angles that are formed between line <math>PQ</math> and lines <math>AB</math> and <math>DC</math> are equal.
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~translated into English by Tomas Diaz. ~orders@tomasdiaz.com
  
 
== Solution ==
 
== Solution ==
 
{{solution}}
 
{{solution}}
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== See also ==
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https://www.oma.org.ar/enunciados/ibe2.htm

Latest revision as of 13:27, 13 December 2023

Problem

Let $ABCD$ be a planar convex quadrilateral, $P$ and $QQ$ are points of $AD$ and $BC$ respectively such that: \[\frac{AP}{PD}=\frac{AB}{DC}=\frac{BQ}{QC}\] Prove that the angles that are formed between line $PQ$ and lines $AB$ and $DC$ are equal.

~translated into English by Tomas Diaz. ~orders@tomasdiaz.com

Solution

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See also

https://www.oma.org.ar/enunciados/ibe2.htm