Difference between revisions of "1995 OIM Problems/Problem 6"
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A function <math>f: N \to N</math> is circular if for every <math>p</math> in <math>N</math> there exists <math>n</math> in <math>N</math> with <math>n \le p</math> such that | A function <math>f: N \to N</math> is circular if for every <math>p</math> in <math>N</math> there exists <math>n</math> in <math>N</math> with <math>n \le p</math> such that | ||
− | <cmath>f^n(p) = f( f( \cdots n | + | <cmath>f^n(p) = f( f( \cdots \text{n times} \cdots f(p))) = p</cmath> |
− | The function f has degree of repulsion <math>k</math>, <math>0 < k<1</math>, if for each <math>p</math> in <math>N</math>, <math>f^i(p) \ne p</math> for <math>i=1, 2, \cdots , \left\lfloor k.p \right\rfloor</math> '''(*)'''. | + | The function <math>f</math> has degree of repulsion <math>k</math>, <math>0 < k<1</math>, if for each <math>p</math> in <math>N</math>, <math>f^i(p) \ne p</math> for <math>i=1, 2, \cdots , \left\lfloor k.p \right\rfloor</math> '''(*)'''. |
Find the greatest degree of repulsion that a circular function can have. | Find the greatest degree of repulsion that a circular function can have. |
Latest revision as of 13:57, 13 December 2023
Problem
A function is circular if for every in there exists in with such that
The function has degree of repulsion , , if for each in , for (*).
Find the greatest degree of repulsion that a circular function can have.
Note (*): indicates the largest integer less than or equal to .
~translated into English by Tomas Diaz. ~orders@tomasdiaz.com
Solution
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