Difference between revisions of "2002 AMC 12P Problems/Problem 17"
(→See also) |
(→Problem) |
||
Line 1: | Line 1: | ||
== Problem == | == Problem == | ||
− | + | If <math>a,b,c</math> are real numbers such that <math>a^2 + 2b =7</math>, <math>b^2 + 4c= -7,</math> and <math>c^2 + 6a= -14</math>, find <math>a^2 + b^2 + c^2.</math> | |
− | <math> \ | + | <math> |
+ | \text{(A) }14 | ||
+ | \qquad | ||
+ | \text{(B) }21 | ||
+ | \qquad | ||
+ | \text{(C) }28 | ||
+ | \qquad | ||
+ | \text{(D) }35 | ||
+ | \qquad | ||
+ | \text{(E) }49 | ||
+ | </math> | ||
== Solution == | == Solution == |
Revision as of 23:51, 29 December 2023
Problem
If are real numbers such that , and , find
Solution
If , then . Since , must be to some factor of 6. Thus, there are four (3, 9, 27, 729) possible values of .
See also
2002 AMC 12P (Problems • Answer Key • Resources) | |
Preceded by Problem 16 |
Followed by Problem 18 |
1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 | |
All AMC 12 Problems and Solutions |
The problems on this page are copyrighted by the Mathematical Association of America's American Mathematics Competitions.