Difference between revisions of "2002 AMC 12P Problems/Problem 17"
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== Solution 2 (Cheese)== | == Solution 2 (Cheese)== | ||
| − | We don't actually have to solve the question. Just let <math>x</math> equal some easy value to calculate <math>\cos {x}, \cos {2x}, \sin {x}, \sin {\frac{x}{2}}</math> and <math>\cos {\frac{x}{2}}.</math> For this solution, let <math>x=60^\circ.</math> This means that the expression in the problem will give | + | We don't actually have to solve the question. Just let <math>x</math> equal some easy value to calculate <math>\cos {x}, \cos {2x}, \sin {x}, \sin {\frac{x}{2}},</math> and <math>\cos {\frac{x}{2}}.</math> For this solution, let <math>x=60^\circ=\frac{\pi}{3}.</math> This means that the expression in the problem will give \sqrt{\frac{\sqrt{3}}{2})^4 + 4(\frac |
== See also == | == See also == | ||
{{AMC12 box|year=2002|ab=P|num-b=16|num-a=18}} | {{AMC12 box|year=2002|ab=P|num-b=16|num-a=18}} | ||
{{MAA Notice}} | {{MAA Notice}} | ||
Revision as of 01:09, 31 December 2023
Problem
Let 
An equivalent form of 
is
Solution 2 (Cheese)
We don't actually have to solve the question. Just let 
equal some easy value to calculate 
and 
For this solution, let 
This means that the expression in the problem will give \sqrt{\frac{\sqrt{3}}{2})^4 + 4(\frac
See also
| 2002 AMC 12P (Problems • Answer Key • Resources) | |
| Preceded by Problem 16 |
Followed by Problem 18 |
| 1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 | |
| All AMC 12 Problems and Solutions | |
The problems on this page are copyrighted by the Mathematical Association of America's American Mathematics Competitions. 
