Difference between revisions of "Solution to Principle of Insufficient Reason Introductory Problem 1"
m |
|||
Line 1: | Line 1: | ||
+ | ==Problem 1== | ||
<math>\text{Principle of Insufficient Reason} \implies \text{max} ([\text{hexagon}])=[\text{Regular Hexagon}]=\boxed{\frac{3}{2} \sqrt{3}}</math> | <math>\text{Principle of Insufficient Reason} \implies \text{max} ([\text{hexagon}])=[\text{Regular Hexagon}]=\boxed{\frac{3}{2} \sqrt{3}}</math> | ||
+ | ==Olympaid problem== | ||
+ | Principle of Insufficient Reason <math>\implies</math> the max of <math>e</math> is achieved when <math>a=b=c=d</math> so <cmath>4a+e=8</cmath> <cmath>4a^2+e^2=16</cmath>. Solving gives <math>e=\frac{16}{5}</math> |
Revision as of 23:09, 19 January 2024
Problem 1
Olympaid problem
Principle of Insufficient Reason the max of
is achieved when
so
. Solving gives