Difference between revisions of "1985 AJHSME Problems/Problem 1"
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− | Notice that the <math>9 \times 11</math> in the denominator of the first fraction cancels with the same term in the second fraction, | + | Notice that the <math>9 \times 11</math> in the denominator of the first fraction cancels with the same term in the second fraction, the <math>7</math>s in the numerator and denominator of the second fraction cancel, and the <math>3 \times 5</math> in the numerator of the first fraction cancels with the same term in the denominator second fraction. Then everything in the expression cancels, leaving us with <math>\boxed{\textbf{(A)}~1}</math>. |
~ [https://artofproblemsolving.com/wiki/index.php/User:Cxsmi cxsmi] | ~ [https://artofproblemsolving.com/wiki/index.php/User:Cxsmi cxsmi] |
Revision as of 12:41, 4 April 2024
Problem
Solution 1
By the associative property, we can rearrange the numbers in the numerator and the denominator.
Solution 2
Notice that the in the denominator of the first fraction cancels with the same term in the second fraction, the s in the numerator and denominator of the second fraction cancel, and the in the numerator of the first fraction cancels with the same term in the denominator second fraction. Then everything in the expression cancels, leaving us with .
~ cxsmi
Video Solution by BoundlessBrain!
See Also
1985 AJHSME (Problems • Answer Key • Resources) | ||
Preceded by First Question |
Followed by Problem 2 | |
1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 | ||
All AJHSME/AMC 8 Problems and Solutions |
The problems on this page are copyrighted by the Mathematical Association of America's American Mathematics Competitions.