Difference between revisions of "2023 IOQM/Problem 2"
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==Problem== | ==Problem== | ||
− | Find the number of elements in the set | + | Find the number of [[elements]] in the [[set]] |
− | < | + | <cmath>\lbrace(a.b)\in N: 2 \leq a,b \leq2023,\:\: \log_{a}{b}+6\log_{b}{a}=5\rbrace</cmath> |
− | == | + | ==Solution1(Quick)== |
+ | Finding the no. of [[elements]] in the [[set]] means finding no. of [[ordered pairs]] of (<math>a</math>, <math>b</math>) | ||
+ | |||
+ | <math>\log_{a}{b}=x</math> Then, <math>\log_{b}{a}=\frac{1}{x}</math>. | ||
+ | |||
+ | <math>\implies</math> <math>x+\frac{6}{x}=5</math>. Upon simplifying, we get <math>x^{2}-5x+6=0</math> | ||
+ | |||
+ | <math>\implies</math> <math>(x-2)(x-3)=0</math> | ||
+ | |||
+ | So, <math>x</math> equals to 2 or 3 | ||
+ | |||
+ | For <math>x</math> = 2, it implies that <math>\log_{a}{b}=2</math>. So, <math>b\:=\: a^{2}</math>, Hence all such pairs are of the form (<math>a</math>,<math>a^{2}</math>) | ||
+ | |||
+ | Where each number lies between 2 and 2023 (inclusive). All such pairs are (2, 4);(3, 9);(4, 16);........(44, 1936) | ||
+ | |||
+ | Total no. of these pairs = 43 | ||
+ | |||
+ | For <math>x</math> = 3, Following a similar pattern, we get the pairs as {2,8}...{12,1728} (<math>a</math>,<math>a^{3}</math>) | ||
+ | |||
+ | Total no. of these pairs = 11 | ||
+ | |||
+ | Thus, there are 43+11=<math>\boxed{54}</math> elements in the set | ||
+ | |||
+ | ~ SANSGANKRSNGUPTA AND ~Andy666 | ||
+ | |||
+ | ==Video Solutions== | ||
+ | Video solution by cheetna: https://www.youtube.com/watch?v=z0NPa0tUzZk | ||
+ | |||
+ | Video solution by Unacademy Olympiad Corner: https://www.youtube.com/watch?v=Mm6mXjwU9bY | ||
+ | |||
+ | Video solution by Vedantu Olympiad School: https://www.youtube.com/watch?v=4DJXtR4VHEA | ||
+ | |||
+ | Video solution by Olympiad Wallah: https://www.youtube.com/watch?v=4HSjmY7d3nA | ||
+ | |||
+ | Video solution by : Motion Olympiad Foundation Class 5th - 10th: https://www.youtube.com/watch?v=oVaeHceHXsQ | ||
+ | |||
+ | '''Please note that above videos solutions are in Hindi, some in English and some in mixed(Hindi + English).''' | ||
+ | |||
+ | ~SANSGANKRSNGUPTA | ||
+ | |||
+ | ==See Also== | ||
+ | [[IOQM]] | ||
+ | |||
+ | [[Mathematics competitions]] | ||
+ | |||
+ | '''Please note that all problems on this page are copyrighted by THE [https://www.mtai.org.in | MTA(I)]''' |
Latest revision as of 02:48, 4 May 2024
Problem
Find the number of elements in the set
Solution1(Quick)
Finding the no. of elements in the set means finding no. of ordered pairs of (,
)
Then,
.
. Upon simplifying, we get
So, equals to 2 or 3
For = 2, it implies that
. So,
, Hence all such pairs are of the form (
,
)
Where each number lies between 2 and 2023 (inclusive). All such pairs are (2, 4);(3, 9);(4, 16);........(44, 1936)
Total no. of these pairs = 43
For = 3, Following a similar pattern, we get the pairs as {2,8}...{12,1728} (
,
)
Total no. of these pairs = 11
Thus, there are 43+11= elements in the set
~ SANSGANKRSNGUPTA AND ~Andy666
Video Solutions
Video solution by cheetna: https://www.youtube.com/watch?v=z0NPa0tUzZk
Video solution by Unacademy Olympiad Corner: https://www.youtube.com/watch?v=Mm6mXjwU9bY
Video solution by Vedantu Olympiad School: https://www.youtube.com/watch?v=4DJXtR4VHEA
Video solution by Olympiad Wallah: https://www.youtube.com/watch?v=4HSjmY7d3nA
Video solution by : Motion Olympiad Foundation Class 5th - 10th: https://www.youtube.com/watch?v=oVaeHceHXsQ
Please note that above videos solutions are in Hindi, some in English and some in mixed(Hindi + English).
~SANSGANKRSNGUPTA
See Also
Please note that all problems on this page are copyrighted by THE | MTA(I)