Difference between revisions of "File:Triangle area ratio lemma.jpg"
Amitwa.exe (talk | contribs) (If in a $\triangle ABC, D,E$ and $F$ are on $AB, BC, AC$ such that $AD:DB=1:a, BE:EC=1:b$ and $FC:FA=1:c$ Then $[DEF]=\left|\frac{[ABC](1+abc)}{(1+a)(1+b)(1+c)}\right|$) |
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Latest revision as of 04:56, 19 May 2024
Summary
If in a $\triangle ABC, D,E$ and $F$ are on $AB, BC, AC$ such that $AD:DB=1:a, BE:EC=1:b$ and $FC:FA=1:c$ Then $[DEF]=\left|\frac{[ABC](1+abc)}{(1+a)(1+b)(1+c)}\right|$
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| Date/Time | Thumbnail | Dimensions | User | Comment | |
|---|---|---|---|---|---|
| current | 04:56, 19 May 2024 |  | 658 × 602 (22 KB) | Amitwa.exe (talk | contribs) | If in a $\triangle ABC, D,E$ and $F$ are on $AB, BC, AC$ such that $AD:DB=1:a, BE:EC=1:b$ and $FC:FA=1:c$ Then $[DEF]=\left|\frac{[ABC](1+abc)}{(1+a)(1+b)(1+c)}\right|$ |
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