Difference between revisions of "User:Johnxyz1"

(Created page with "Below are some stuff I am doing to practice <math>\LaTeX</math> (that logo typeset by <code>\LaTeX</code> looks a bit off). <cmath>\text{If }ax^2+bx+c=0\text{, then }x=\frac{...")
 
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Below are some stuff I am doing to practice <math>\LaTeX</math> (that logo typeset by <code>\LaTeX</code> looks a bit off).
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Below are some stuff I am doing to practice <math>\LaTeX</math> (that logo typeset by <code>\LaTeX</code> looks a bit off). That does not mean I know all of it.
  
 
<cmath>\text{If }ax^2+bx+c=0\text{, then }x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}</cmath>
 
<cmath>\text{If }ax^2+bx+c=0\text{, then }x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}</cmath>
 
<cmath>e^{i\pi}+1=0</cmath>
 
<cmath>e^{i\pi}+1=0</cmath>
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<cmath>\sum_{x=1}^{\infty} \frac{1}{x}=2</cmath>
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<cmath>\begin{align*}
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x &= \sqrt[3]{\left(\frac{-b^3}{27a^3} + \frac{bc}{6a^2} - \frac{d}{2a}\right) + \sqrt{\left(\frac{-b^3}{27a^3} + \frac{bc}{6a^2} - \frac{d}{2a}\right)^2 + \left(\frac{c}{3a} - \frac{b^2}{9a^2}\right)^3}} \
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&+ \sqrt[3]{\left(\frac{-b^3}{27a^3} + \frac{bc}{6a^2} - \frac{d}{2a}\right) - \sqrt{\left(\frac{-b^3}{27a^3} + \frac{bc}{6a^2} - \frac{d}{2a}\right)^2 + \left(\frac{c}{3a} - \frac{b^2}{9a^2}\right)^3}} - \frac{b}{3a} \
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&\text{(I copied it from another website but I typeset it myself; I am pretty sure those are not copyrightable. I still need \textit{years} to understand this.)}
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\end{align*}
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</cmath>

Revision as of 19:26, 21 June 2024

Below are some stuff I am doing to practice $\LaTeX$ (that logo typeset by \LaTeX looks a bit off). That does not mean I know all of it.

\[\text{If }ax^2+bx+c=0\text{, then }x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}\] \[e^{i\pi}+1=0\] \[\sum_{x=1}^{\infty} \frac{1}{x}=2\] \begin{align*} x &= \sqrt[3]{\left(\frac{-b^3}{27a^3} + \frac{bc}{6a^2} - \frac{d}{2a}\right) + \sqrt{\left(\frac{-b^3}{27a^3} + \frac{bc}{6a^2} - \frac{d}{2a}\right)^2 + \left(\frac{c}{3a} - \frac{b^2}{9a^2}\right)^3}} \\ &+ \sqrt[3]{\left(\frac{-b^3}{27a^3} + \frac{bc}{6a^2} - \frac{d}{2a}\right) - \sqrt{\left(\frac{-b^3}{27a^3} + \frac{bc}{6a^2} - \frac{d}{2a}\right)^2 + \left(\frac{c}{3a} - \frac{b^2}{9a^2}\right)^3}} - \frac{b}{3a} \\ &\text{(I copied it from another website but I typeset it myself; I am pretty sure those are not copyrightable. I still need \textit{years} to understand this.)} \end{align*}