Difference between revisions of "Symmedians, Lemoine point"
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Similarly, one can get <math>[DLE] = [DLF] = [DEF] = k^2 [ABC] \implies L</math> is the centroid of <math>\triangle DEF.</math> | Similarly, one can get <math>[DLE] = [DLF] = [DEF] = k^2 [ABC] \implies L</math> is the centroid of <math>\triangle DEF.</math> | ||
+ | |||
+ | <i><b>Corollary</b></i> | ||
+ | |||
+ | Vector sum <math>\vec {LE} + \vec {LD} + \vec {LF} = \vec 0.</math> | ||
+ | |||
+ | Each of these vectors is obtained from the triangle side vectors by rotating by <math>90^\circ</math> and multiplying by a constant <math>k^2,</math> | ||
+ | <cmath>\vec {AC} + \vec {CB} + \vec {BA} = \vec 0.</cmath> | ||
'''vladimir.shelomovskii@gmail.com, vvsss''' | '''vladimir.shelomovskii@gmail.com, vvsss''' |
Revision as of 05:09, 20 July 2024
The reflecting of the median over the corresponding angle bisector is the symmedian. The angle formed by the symmedian and the angle bisector has the same measure as the angle between the median and the angle bisector, but it is on the other side of the angle bisector. The symmedian is isogonally conjugate to the median
There are three symmedians. They are meet at a triangle center called the Lemoine point.
Proportions
Let be given.
Let be the median,
Prove that iff is the symmedian than
Proof
1. Let be the symmedian. So Similarly
By applying the Law of Sines we get Similarly,
2.
As point moves along the fixed arc from to , the function monotonically increases from zero to infinity. This means that there is exactly one point at which the condition is satisfied. In this case, point lies on the symmedian.
Similarly for point
Corollary
Let be the symmedian of
Then is the symmedian of is the symmedian of is the symmedian of
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Symmedian and tangents
Let and it’s circumcircle be given.
Tangents to at points and intersect at point
Prove that is symmedian of
Proof
Denote WLOG, is symmedian of
Corollary
Let and it’s circumcircle be given.
Let tangent to at points intersect line at point
Let be the tangent to different from
Then is symmedian of
vladimir.shelomovskii@gmail.com, vvsss
Lemoine point properties
Let be given. Let be the Lemoine point of
Prove that is the centroid of
Proof
Let be the centroid of
The double area of is
Point is the isogonal conjugate of point with respect to
Similarly, one can get
The double area of is
Similarly, one can get is the centroid of
Corollary
Vector sum
Each of these vectors is obtained from the triangle side vectors by rotating by and multiplying by a constant
vladimir.shelomovskii@gmail.com, vvsss