Difference between revisions of "2024 AMC 10A Problems/Problem 25"

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<math>\sqrt{\text{sigma}}</math>
 
<math>\sqrt{\text{sigma}}</math>
  
<math>\textbf{(A) } alpha \qquad\textbf{(B) } \text{rizzler} \qquad\textbf{(C) } \text{skibidi toilet} \qquad\textbf{(D) }\text{fanum tax} /qquad\textbf{(E) }\text{Mew} /qquad\textbf{(F) }\text{looksmaxxing} /qquad\textbf{(G) }\text{the ohio sigma fanum tax rizzler with a infinite mewing streak}</math>
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<math>\textbf{(A) } alpha \qquad\textbf{(B) } \text{rizzler} \qquad\textbf{(C) } \text{skibidi toilet} \qquad\textbf{(D) }\text{fanum tax} /qquad \textbf{(E) }\text{Mew} /qquad \textbf{(F) }\text{looksmaxxing} /qquad \textbf{(G) }\text{the ohio sigma fanum tax rizzler with a infinite mewing streak}</math>

Revision as of 10:57, 2 August 2024

$\sqrt{\text{sigma}}$

$\textbf{(A) } alpha \qquad\textbf{(B) } \text{rizzler} \qquad\textbf{(C) } \text{skibidi toilet} \qquad\textbf{(D) }\text{fanum tax} /qquad \textbf{(E) }\text{Mew} /qquad \textbf{(F) }\text{looksmaxxing} /qquad \textbf{(G) }\text{the ohio sigma fanum tax rizzler with a infinite mewing streak}$