Difference between revisions of "Surface of constant width"

(Reuleaux triangle)
(Reuleaux triangle)
Line 14: Line 14:
  
 
Distance is <math>|AB|.</math>
 
Distance is <math>|AB|.</math>
 +
 +
'''vladimir.shelomovskii@gmail.com, vvsss'''
 +
==Reuleaux triangle analogue==
 +
[[File:Reuleaux triangle analogue.png|350px|right]]
 +
Let <math>ABCD</math> be the boundary of a Reuleaux triangle, <math>O</math> be the centroid of <math>\triangle ABC.</math>
 +
 +
Let <math>\overset{\Large\frown} {FF_0}</math> be the arc centered at <math>A</math> with radius <math>AA', \angle FAF_0 = 60^\circ,</math> points <math>F, A, C</math> and <math>F_0, A, B</math> are collinear.
 +
 +
Let <math>\overset{\Large\frown} {F_0F'}</math> be the arc centered at <math>B</math> with radius <cmath>|AA'| + |AB|,</cmath>
 +
<math>\angle F'AF_0 = \angle ABC = 60^\circ,</math> points <math>F', C, B</math> are collinear.
 +
 +
Similarly define arcs from point <math>F'</math> to <math>F.</math>
 +
 +
The width of this curve is <cmath>|AB| + 2|AA'|.</cmath>
 +
 +
'''vladimir.shelomovskii@gmail.com, vvsss'''

Revision as of 07:32, 10 August 2024

A curve of constant width is a simple closed curve in the plane whose width (the distance between parallel supporting lines) is the same in all directions. A surface of constant width (orbiform) is a convex form whose width, measured by the distance between two opposite parallel planes touching its boundary, is the same regardless of the direction of those two parallel planes.

Reuleaux triangle

Reuleaux triangle.png

The boundary of a Reuleaux triangle is a constant width curve based on an equilateral triangle.

Let $\triangle ABC$ be equilateral triangle.

Let $\overset{\Large\frown} {AC}$ be the arc centered at $B$ with radius $BB' = BA, \angle ABC = 60^\circ.$

Arcs $\overset{\Large\frown} {AB}$ and $\overset{\Large\frown} {BC}$ define similarly.

All points on this arcs are equidistant from the opposite vertex.

Distance is $|AB|.$

vladimir.shelomovskii@gmail.com, vvsss

Reuleaux triangle analogue

Reuleaux triangle analogue.png

Let $ABCD$ be the boundary of a Reuleaux triangle, $O$ be the centroid of $\triangle ABC.$

Let $\overset{\Large\frown} {FF_0}$ be the arc centered at $A$ with radius $AA', \angle FAF_0 = 60^\circ,$ points $F, A, C$ and $F_0, A, B$ are collinear.

Let $\overset{\Large\frown} {F_0F'}$ be the arc centered at $B$ with radius \[|AA'| + |AB|,\] $\angle F'AF_0 = \angle ABC = 60^\circ,$ points $F', C, B$ are collinear.

Similarly define arcs from point $F'$ to $F.$

The width of this curve is \[|AB| + 2|AA'|.\]

vladimir.shelomovskii@gmail.com, vvsss