Difference between revisions of "2024 AMC 10A Problems/Problem 25"

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<math>\sqrt{\text{sigma}}</math>
 
<math>\sqrt{\text{sigma}}</math>
  
<math>\textbf{(A) } alpha \qquad\textbf{(B) } \text{rizzler} \qquad\textbf{(C) } \text{skibidi toilet} \qquad\textbf(D) }\text{fanum tax}</math>
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<math>\textbf{(A) } alpha \qquad\textbf{(B) } \text{rizzler} \qquad\textbf{(C) } \text{skibidi toilet} \qquad\textbf{(D) }\text{fanum tax}  
 +
\qquad\textbf{(E) }\text{Mew} \qquad\textbf{(F) }\text{looksmaxxing}</math>
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==Solution 1==
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Skibidi toilet with a infite mewing streak
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+1000000 aura skibidi toilet kai cenat caseoh
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==Solution 2==
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<math>\Sigma</math>

Latest revision as of 09:33, 26 August 2024

$\sqrt{\text{sigma}}$

$\textbf{(A) } alpha \qquad\textbf{(B) } \text{rizzler} \qquad\textbf{(C) } \text{skibidi toilet} \qquad\textbf{(D) }\text{fanum tax}   \qquad\textbf{(E) }\text{Mew} \qquad\textbf{(F) }\text{looksmaxxing}$

Solution 1

Skibidi toilet with a infite mewing streak

+1000000 aura skibidi toilet kai cenat caseoh

Solution 2

$\Sigma$