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Difference between revisions of "2024 AMC 10A Problems/Problem 25"
(Undo revision 225182 by Emchang (talk))
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<math>\sqrt{\text{sigma}}</math>
 
<math>\sqrt{\text{sigma}}</math>
  
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<math>\textbf{(A) } alpha \qquad\textbf{(B) } \text{rizzler} \qquad\textbf{(C) } \text{skibidi toilet} \qquad\textbf{(D) }\text{fanum tax} /qquad\textbf{(E) }\text{Mew} /qquad\textbf{(F) }\text{looksmaxxing} /qquad\textbf{(G) }\text{the ohio sigma fanum tax rizzler with a infinite mewing streak}</math>
+
<math>\textbf{(A) } alpha \qquad\textbf{(B) } \text{rizzler} \qquad\textbf{(C) } \text{skibidi toilet} \qquad\textbf{(D) }\text{fanum tax}  
 +
\qquad\textbf{(E) }\text{Mew} \qquad\textbf{(F) }\text{looksmaxxing}</math>
 +
 
 +
==Solution 1==
 +
 
 +
Skibidi toilet with a infite mewing streak
 +
 
 +
+1000000 aura skibidi toilet kai cenat caseoh
 +
 
 +
==Solution 2==
 +
<math>\Sigma</math>

Revision as of 08:33, 26 August 2024

$\sqrt{\text{sigma}}$

$\textbf{(A) } alpha \qquad\textbf{(B) } \text{rizzler} \qquad\textbf{(C) } \text{skibidi toilet} \qquad\textbf{(D) }\text{fanum tax} \qquad\textbf{(E) }\text{Mew} \qquad\textbf{(F) }\text{looksmaxxing}$

Solution 1

Skibidi toilet with a infite mewing streak

+1000000 aura skibidi toilet kai cenat caseoh

Solution 2

$\Sigma$

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