Difference between revisions of "2000 AMC 8 Problems/Problem 24"
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| + | ==Problem== | ||
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If <math> \angle A = 20^\circ </math> and <math> \angle AFG =\angle AGF </math>, then <math> \angle B+\angle D = </math> | If <math> \angle A = 20^\circ </math> and <math> \angle AFG =\angle AGF </math>, then <math> \angle B+\angle D = </math> | ||
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label("$G$",G,NW);</asy> | label("$G$",G,NW);</asy> | ||
| − | + | $ \text{(A)}\ 48^\circ\qquad\text{(B)}\ 60^\circ\qquad\text{(C)}\ 72^\circ\qquad\text{(D)}\ 80^\ | |
| + | |||
| + | == Video Solution == | ||
| + | https://www.youtube.com/watch?v=8ntXubG2Iho ~David | ||
| + | |||
| + | ==See Also== | ||
| + | |||
| + | {{AMC8 box|year=2000|num-b=23|num-a=25}} | ||
| + | {{MAA Notice}} | ||
Revision as of 19:56, 1 September 2024
Problem
If 
and 
, then 
![[asy] pair A,B,C,D,EE,F,G; A = (0,0); B = (9,4); C = (21,0); D = (13,-12); EE = (4,-16); F = (13/2,-6); G = (8,0); draw(A--C--EE--B--D--cycle); label("$A$",A,W); label("$B$",B,N); label("$C$",C,E); label("$D$",D,SE); label("$E$",EE,SW); label("$F$",F,WSW); label("$G$",G,NW);[/asy]](http://latex.artofproblemsolving.com/8/2/8/8289a149effe74716d870e23680293e2397d8132.png)
$ \text{(A)}\ 48^\circ\qquad\text{(B)}\ 60^\circ\qquad\text{(C)}\ 72^\circ\qquad\text{(D)}\ 80^\
Video Solution
https://www.youtube.com/watch?v=8ntXubG2Iho ~David
See Also
| 2000 AMC 8 (Problems • Answer Key • Resources) | ||
| Preceded by Problem 23 |
Followed by Problem 25 | |
| 1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 | ||
| All AJHSME/AMC 8 Problems and Solutions | ||
The problems on this page are copyrighted by the Mathematical Association of America's American Mathematics Competitions. 
