Difference between revisions of "1985 AJHSME Problems/Problem 3"
(→Solution) |
(→Solution 2) |
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Line 20: | Line 20: | ||
So the answer is <math>\boxed{\text{D}}</math> | So the answer is <math>\boxed{\text{D}}</math> | ||
− | == Solution 2 == | + | == Solution 2 (Brute Force) == |
+ | |||
+ | <math>10^7</math> is <math>10000000</math> | ||
+ | |||
+ | <math>5 \times 10^4</math> is <math>50000</math> | ||
+ | |||
+ | Thus the answer is <math>2000</math> | ||
==Video Solution by BoundlessBrain!== | ==Video Solution by BoundlessBrain!== |
Revision as of 21:06, 2 October 2024
Contents
Problem
Solution
We immediately see some canceling. We see powers of ten on the top and on the bottom of the fraction, and we make quick work of this:
We know that , so
So the answer is
Solution 2 (Brute Force)
is
is
Thus the answer is
Video Solution by BoundlessBrain!
Video Solution
~savannahsolver
See Also
1985 AJHSME (Problems • Answer Key • Resources) | ||
Preceded by Problem 2 |
Followed by Problem 4 | |
1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 | ||
All AJHSME/AMC 8 Problems and Solutions |
The problems on this page are copyrighted by the Mathematical Association of America's American Mathematics Competitions.