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Difference between revisions of "1985 AJHSME Problems/Problem 3"

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So the answer is <math>\boxed{\text{D}}</math>
 
So the answer is <math>\boxed{\text{D}}</math>
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== Solution 2 (Brute Force) ==
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<math>10^7</math> is <math>10000000</math>
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<math>5 \times 10^4</math> is <math>50000</math>
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Thus the answer is <math>200</math>, or <math>\boxed{\textbf{(D)}\ 200}</math>
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==Video Solution by BoundlessBrain!==
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https://youtu.be/BfFv227egOg
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==Video Solution==
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https://youtu.be/KW5HexBjEHU
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~savannahsolver
  
 
==See Also==
 
==See Also==
  
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[[1985 AJHSME Problems]]
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{{AJHSME box|year=1985|num-b=2|num-a=4}}
  
 
[[Category:Introductory Algebra Problems]]
 
[[Category:Introductory Algebra Problems]]
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{{MAA Notice}}

Latest revision as of 21:07, 2 October 2024

Problem

$\frac{10^7}{5\times 10^4}=$


$\text{(A)}\ .002 \qquad \text{(B)}\ .2 \qquad \text{(C)}\ 20 \qquad \text{(D)}\ 200 \qquad \text{(E)}\ 2000$

Solution

We immediately see some canceling. We see powers of ten on the top and on the bottom of the fraction, and we make quick work of this: \[\frac{10^7}{5 \times 10^4} = \frac{10^3}{5}\]

We know that $10^3 = 10 \times 10 \times 10$, so

\begin{align*} \frac{10^3}{5} &= \frac{10\times 10\times 10}{5} \\ &= 2\times 10\times 10 \\ &= 200 \\ \end{align*}

So the answer is $\boxed{\text{D}}$

Solution 2 (Brute Force)

$10^7$ is $10000000$

$5 \times 10^4$ is $50000$

Thus the answer is $200$, or $\boxed{\textbf{(D)}\ 200}$

Video Solution by BoundlessBrain!

https://youtu.be/BfFv227egOg

Video Solution

https://youtu.be/KW5HexBjEHU

~savannahsolver

See Also

1985 AJHSME (Problems • Answer Key • Resources)
Preceded by
Problem 2 		Followed by
Problem 4
1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25
All AJHSME/AMC 8 Problems and Solutions


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