Difference between revisions of "2024 AMC 12B Problems/Problem 14"

(Created page with "We split the cases into: 1. If x is not a multiple of 5: we get x^100 \equiv 1 (mod 125) 2. If x is a multiple of 125: Clearly the only remainder provides 0 Therefore, the rem...")
 
(Redirected page to 2024 AMC 10B Problems/Problem 18)
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We split the cases into:
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#REDIRECT[[2024 AMC 10B Problems/Problem 18]]
1. If x is not a multiple of 5:
 
we get x^100 \equiv 1 (mod 125)
 
2. If x is a multiple of 125:
 
Clearly the only remainder provides 0
 
Therefore, the remainders can only be 1 and 2, which gives the answer (B)2
 

Latest revision as of 01:24, 14 November 2024