Difference between revisions of "2024 AMC 12B Problems/Problem 14"

Latest revision as of 01:24, 14 November 2024

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-We split the cases into:
+#REDIRECT[[2024 AMC 10B Problems/Problem 18]]
-. If x is not a multiple of 5:
-we get x^100\equiv 1 (mod 125)
-. If x is a multiple of 125:
-Clearly the only remainder provides 0
-Therefore, the remainders can only be 1 and 0, which gives the answer (B)2
-~mitsuihisashi14