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Difference between revisions of "2025 AMC 8 Problems/Problem 1"

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Let m and n be 2 integers such that m > n. Suppose m + n = 20, m² + n² = 328, find m² - n².
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The 2025 AMC 8 is not held yet. '''Please do not post false problems.'''
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A) 280
 
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B) 292
 
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C) 300
 
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D) 320
 
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E) 340
 
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<math>\textbf{(A)}\ 280 \qquad \textbf{(B)}\ 292 \qquad \textbf{(C)}\ 300 \qquad \textbf{(D)}\ 320 \qquad \textbf{(E)}\ 340</math>
 

Latest revision as of 18:16, 20 December 2024

The 2025 AMC 8 is not held yet. Please do not post false problems.

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