Difference between revisions of "2025 AMC 8 Problems/Problem 11"

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Find the smallest positive integer <math>k</math> such that <math>(2^{91}+k)</math> is divisible by <math>127</math>.
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The 2025 AMC 8 is not held yet. Please do not post false problems.
 
 
<math>\textbf{(A)}\ 122 \qquad \textbf{(B)}\ 123 \qquad \textbf{(C)}\ 124 \qquad \textbf{(D)}\ 125 \qquad \textbf{(E)}\ 126</math>
 

Latest revision as of 18:16, 20 December 2024

The 2025 AMC 8 is not held yet. Please do not post false problems.