Difference between revisions of "2004 AMC 10A Problems/Problem 9"

Latest revision as of 20:57, 23 April 2008

Redirect to:

@@ Line 1: / Line 1: @@
-==Problem==
+#redirect [[2004 AMC 12A Problems/Problem 8]]
-In the figure, <math>\angle EAB</math> and <math>\angle ABC</math> are right angles. <math>AB=4, BC=6, AE=8</math>, and <math>AC</math> and <math>BE</math> intersect at <math>D</math>. What is the difference between the areas of <math>\triangle ABC</math> and <math>\triangle BDC</math>?
-<center>[[Image:AMC10_2004A_9.gif]]</center>
-==Solution==
-{{solution}}
-== See also ==
-* [http://www.artofproblemsolving.com/Forum/viewtopic.php?t=131320 AoPS topic]
-{{AMC10 box|year=2004|ab=A|num-b=8|num-a=10}}