Difference between revisions of "2008 AMC 10A Problems/Problem 17"
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Three rectangles are formed that are <math>3*6</math>. <math>3*3*6=54</math>. <math>360-90-90-60=120</math> degrees = <math>1/3</math> the circle's area. <math>1/3*3= 1</math> circle's area, <math>9 \pi</math>. | Three rectangles are formed that are <math>3*6</math>. <math>3*3*6=54</math>. <math>360-90-90-60=120</math> degrees = <math>1/3</math> the circle's area. <math>1/3*3= 1</math> circle's area, <math>9 \pi</math>. |
Revision as of 07:12, 16 June 2008
Problem
An equilateral triangle has side length 6. What is the area of the region containing all points that are outside the triangle but not more than 3 units from a point of the triangle?
$\mathrm{(A)}\ 36+24\sqrt{3}\qquad\mathrm{(B)}\ 54+9\pi\qquad\mathrm{(C)}\ 54+18\sqrt{3}+6\pi\qquad\mathrm{(D)}\ \left(2\sqrt{3}+3\right)^2\pi\\mathrm{(E)}\ 9\left(\sqrt{3}{+1\right)^2\pi$ (Error compiling LaTeX. Unknown error_msg)
Solution
Three rectangles are formed that are . . degrees = the circle's area. circle's area, .
B
See also
2008 AMC 10A (Problems • Answer Key • Resources) | ||
Preceded by Problem 16 |
Followed by Problem 18 | |
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All AMC 10 Problems and Solutions |