Difference between revisions of "Uncountable"

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== Proof that <math>\mathbb{R}</math> is uncountable ==
 
== Proof that <math>\mathbb{R}</math> is uncountable ==
  
We give an indirect proof here. This is one of the most famous indirect proofs and was given by George Cantor.
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We give an [[indirect proof]] here. This is one of the most famous indirect proofs and was first given by [[Georg Cantor]].
  
 
Suppose that the set <math>A=\{x\in\mathbb{R}:0<x< 1\}</math> is countable. Let <math>\{\omega_1, \omega_2, \omega_3, ...\}</math> be any  enumeration of the elements of <math>A</math>. Consider the binary expansion of each <math>\omega_i</math>. For dyadic rationals, take only the expansion terminating in an infinite chain of zeros, so that we have a unique binary expansion for each element of <math>A</math>. Say <math>\omega_i=(.b_{i1}b_{i2}b_{i3}...)_2</math> for all <math>i</math>. Now construct <math>\omega=(.b_1b_2b_3...)_2</math> such that <math>b_i=1-b_{ii}</math> for all <math>i</math>. So <math>\omega</math> is different from <math>\omega_i</math> for all <math>i</math>. So <math>\omega\not\in A</math>. But <math>\omega\in\mathbb{R},0<\omega<1</math>, a'' contradiction''. So <math>\mathbb{R}</math> is uncountable.
 
Suppose that the set <math>A=\{x\in\mathbb{R}:0<x< 1\}</math> is countable. Let <math>\{\omega_1, \omega_2, \omega_3, ...\}</math> be any  enumeration of the elements of <math>A</math>. Consider the binary expansion of each <math>\omega_i</math>. For dyadic rationals, take only the expansion terminating in an infinite chain of zeros, so that we have a unique binary expansion for each element of <math>A</math>. Say <math>\omega_i=(.b_{i1}b_{i2}b_{i3}...)_2</math> for all <math>i</math>. Now construct <math>\omega=(.b_1b_2b_3...)_2</math> such that <math>b_i=1-b_{ii}</math> for all <math>i</math>. So <math>\omega</math> is different from <math>\omega_i</math> for all <math>i</math>. So <math>\omega\not\in A</math>. But <math>\omega\in\mathbb{R},0<\omega<1</math>, a'' contradiction''. So <math>\mathbb{R}</math> is uncountable.

Revision as of 09:38, 29 June 2008

A set $S$ is said to be uncountable if there is no injection $f:S\to\mathbb{N}$. A well-known example of an uncountable set is the set of real numbers $\mathbb{R}$.

Proof that $\mathbb{R}$ is uncountable

We give an indirect proof here. This is one of the most famous indirect proofs and was first given by Georg Cantor.

Suppose that the set $A=\{x\in\mathbb{R}:0<x< 1\}$ is countable. Let $\{\omega_1, \omega_2, \omega_3, ...\}$ be any enumeration of the elements of $A$. Consider the binary expansion of each $\omega_i$. For dyadic rationals, take only the expansion terminating in an infinite chain of zeros, so that we have a unique binary expansion for each element of $A$. Say $\omega_i=(.b_{i1}b_{i2}b_{i3}...)_2$ for all $i$. Now construct $\omega=(.b_1b_2b_3...)_2$ such that $b_i=1-b_{ii}$ for all $i$. So $\omega$ is different from $\omega_i$ for all $i$. So $\omega\not\in A$. But $\omega\in\mathbb{R},0<\omega<1$, a contradiction. So $\mathbb{R}$ is uncountable.

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