Difference between revisions of "1966 AHSME Problems/Problem 8"
(New page: ==Problem== The length of the common chord of two intersecting circles is <math>16</math> feet. If the radii are <math>10</math> feet and <math>17</math> feet, a possible value for the dis...) |
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Revision as of 19:37, 1 July 2008
Problem
The length of the common chord of two intersecting circles is feet. If the radii are
feet and
feet, a possible value for the distance between the centers of the circles, expressed in feet, is:
Solution
File:1966 AHSME-8.jpg
Let be the center of the circle of radius
and
be the center of the circle of radius
. Chord
feet.
feet, since they are radii of a circle. Hence,
is isoceles with base
. The height of $\trianlge OAB$ (Error compiling LaTeX. Unknown error_msg) from
to
is