Difference between revisions of "Base Angle Theorem"
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==Proof== | ==Proof== | ||
− | Since the triangle only has three sides, the two equal-measuring sides must be adjacent. Let them meet at vertex <math>A</math>. Now we draw [[height]] <math>AD</math> to <math>BC</math>. From the [[Pythagorean Theorem]], <math>BD=CD</math>, and thus <math>\triangle ABD</math> is similar to <math>\triangle ACD</math>, and <math>\angle DBA=\angle DCA</math>. | + | Since the triangle only has three sides, the two equal-measuring sides must be adjacent. Let them meet at vertex <math>A</math>. |
+ | |||
+ | Now we draw [[height]] <math>AD</math> to <math>BC</math>. From the [[Pythagorean Theorem]], <math>BD=CD</math>, and thus <math>\triangle ABD</math> is similar to <math>\triangle ACD</math>, and <math>\angle DBA=\angle DCA</math>. <asy> | ||
+ | unitsize(5); defaultpen(fontsize(10)); | ||
+ | pair A,B,C,D,E,F,G,H; | ||
+ | A=(0,10); | ||
+ | B=(-5,0); | ||
+ | C=(5,0); | ||
+ | D=(0,0); | ||
+ | E=(1,1); | ||
+ | F=(-1,1); | ||
+ | G=(-1,0); | ||
+ | H=(1,0); | ||
+ | draw(A--B); | ||
+ | draw(B--C); | ||
+ | draw(C--A); | ||
+ | draw(A--D); | ||
+ | draw(E--F); | ||
+ | draw(E--H); | ||
+ | draw(F--G); | ||
+ | label("$A$",A,N); | ||
+ | label("$B$",B,SW); | ||
+ | label("$C$",C,SE); | ||
+ | label("$D$",D,S);</asy> | ||
[[Category:Theorems]] | [[Category:Theorems]] | ||
[[Category:Geometry]] | [[Category:Geometry]] |
Revision as of 15:59, 31 August 2008
The Hinge Theorem states that in an isosceles triangle, the measures of the angles opposite the equal-measuring sides are equal.
Proof
Since the triangle only has three sides, the two equal-measuring sides must be adjacent. Let them meet at vertex .
Now we draw height to . From the Pythagorean Theorem, , and thus is similar to , and .