Difference between revisions of "1951 AHSME Problems/Problem 1"
(New page: == Problem == The percent that <math>M</math> is greater than <math>N</math> is: <math>(\mathrm{A})\ \frac{100(M-N)}{M} \qquad (\mathrm{B})\ \frac{100(M-N)}{N} \qquad (\mathrm{C})\ \frac{...) |
(No difference)
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Revision as of 02:21, 8 February 2009
Problem
The percent that is greater than is:
Solution
is the amount by which is greater than . We divide this by to get the percent by which increased expressed as a decimal, and then multiply by to make it a percentage. Therefore, the answer is .