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Difference between revisions of "1988 AJHSME Problems/Problem 2"

(New page: ==Problem== The product <math>8\times .25\times 2\times .125 =</math> <math>\text{(A)}\ \frac18 \qquad \text{(B)}\ \frac14 \qquad \text{(C)}\ \frac12 \qquad \text{(D)}\ 1 \qquad \text{(E...)
(No difference)

Revision as of 06:30, 13 April 2009

Problem

The product $8\times .25\times 2\times .125 =$

$\text{(A)}\ \frac18 \qquad \text{(B)}\ \frac14 \qquad \text{(C)}\ \frac12 \qquad \text{(D)}\ 1 \qquad \text{(E)}\ 2$

Solution

Converting the decimals to fractions, this is \begin{align*} 8\times \frac{1}{4} \times 2\times \frac{1}{8} &= \frac{8\times 2}{4\times 8} \\ &= \frac{16}{32} \\ &= \frac{1}{2} \rightarrow \boxed{\text{C}} \end{align*}

See Also

1988 AJHSME Problems

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