Difference between revisions of "Fallacious proof/All numbers are equal"
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| − | {{ | + | It does not follow in general from <math>x^2 = y^2</math> that <math>x = y</math>. Instead, we have either that <math>x = y</math> or <math>x = -y</math>. In the given situation, we have that <math>a - \frac{t}{2} = \frac{a - b}{2} = -\left(\frac{b - a}{2}\right) = - \left(b - \frac{t}{2}\right)</math>, and so this was the fallacious step. |
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| + | ''[[Fallacious_proof#All_numbers_are_equal | Back to main article]]'' | ||
Latest revision as of 14:00, 21 July 2009
It does not follow in general from 
that 
. Instead, we have either that or 
. In the given situation, we have that 
, and so this was the fallacious step.
