Difference between revisions of "User:R31415"
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| − | '''<math>e^i | + | '''<math>e^ i\pi=-1</math>''' |
| − | Which means that i^i equals <math>(e^i*e^\pi*e^1/2)^i= e^-\pi/2 | + | Which means that i^i equals <math>(e^i*e^\pi*e^ 1/2)^i= e^-\pi/2 |
| − | </math>(e^i*e^\pi*e^1/2)^i= e^-\pi/2 | + | </math>(e^i*e^\pi*e^1/2)^i= e^-\pi/2$ |
<dollar/><dollar/><dollar/><dollar/><dollar/><dollar/><dollar/><dollar/><dollar/><dollar/><dollar/><dollar/><dollar/><dollar/><dollar/><dollar/><dollar/><dollar/><dollar/><dollar/><dollar/><dollar/><dollar/><dollar/><dollar/><dollar/><dollar/><dollar/><dollar/><dollar/> | <dollar/><dollar/><dollar/><dollar/><dollar/><dollar/><dollar/><dollar/><dollar/><dollar/><dollar/><dollar/><dollar/><dollar/><dollar/><dollar/><dollar/><dollar/><dollar/><dollar/><dollar/><dollar/><dollar/><dollar/><dollar/><dollar/><dollar/><dollar/><dollar/><dollar/> | ||
Revision as of 20:06, 7 January 2011
Which means that i^i equals 
(e^i*e^\pi*e^1/2)^i= e^-\pi/2$
<dollar/><dollar/><dollar/><dollar/><dollar/><dollar/><dollar/><dollar/><dollar/><dollar/><dollar/><dollar/><dollar/><dollar/><dollar/><dollar/><dollar/><dollar/><dollar/><dollar/><dollar/><dollar/><dollar/><dollar/><dollar/><dollar/><dollar/><dollar/><dollar/><dollar/>
