Difference between revisions of "User:R31415"
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− | '''<math>e^ i\pi=-1</math>''' | + | '''<math>e^ i\pi =-1</math>''' |
Which means that i^i equals <math>(e^i*e^\pi*e^ 1/2)^i= e^-\pi/2 | Which means that i^i equals <math>(e^i*e^\pi*e^ 1/2)^i= e^-\pi/2 | ||
</math>(e^i*e^\pi*e^1/2)^i= e^-\pi/2$ | </math>(e^i*e^\pi*e^1/2)^i= e^-\pi/2$ | ||
<dollar/><dollar/><dollar/><dollar/><dollar/><dollar/><dollar/><dollar/><dollar/><dollar/><dollar/><dollar/><dollar/><dollar/><dollar/><dollar/><dollar/><dollar/><dollar/><dollar/><dollar/><dollar/><dollar/><dollar/><dollar/><dollar/><dollar/><dollar/><dollar/><dollar/> | <dollar/><dollar/><dollar/><dollar/><dollar/><dollar/><dollar/><dollar/><dollar/><dollar/><dollar/><dollar/><dollar/><dollar/><dollar/><dollar/><dollar/><dollar/><dollar/><dollar/><dollar/><dollar/><dollar/><dollar/><dollar/><dollar/><dollar/><dollar/><dollar/><dollar/> | ||
+ | <br> ah well... LaTeX is hard... |
Revision as of 20:07, 7 January 2011
Which means that i^i equals (e^i*e^\pi*e^1/2)^i= e^-\pi/2$
<dollar/><dollar/><dollar/><dollar/><dollar/><dollar/><dollar/><dollar/><dollar/><dollar/><dollar/><dollar/><dollar/><dollar/><dollar/><dollar/><dollar/><dollar/><dollar/><dollar/><dollar/><dollar/><dollar/><dollar/><dollar/><dollar/><dollar/><dollar/><dollar/><dollar/>
ah well... LaTeX is hard...