Difference between revisions of "KGS math club/solution 11 1"

(added rest of content)
m
 
Line 6: Line 6:
 
<li>the vertices of an equlateral triangle, plus a point on a symmetry axis that is a side-length away from the vertex through which that axis passes</li>
 
<li>the vertices of an equlateral triangle, plus a point on a symmetry axis that is a side-length away from the vertex through which that axis passes</li>
 
<li>the vertices of an equlateral triangle, plus a point on a symmetry axis that is a side-length away, in the opposite direction, from the vertex through which that axis passes</li>
 
<li>the vertices of an equlateral triangle, plus a point on a symmetry axis that is a side-length away, in the opposite direction, from the vertex through which that axis passes</li>
<li>Four of the vertices of a pentagon</li>
+
<li>Four of the vertices of a regular pentagon</li>
 
</ol>
 
</ol>

Latest revision as of 11:08, 11 May 2011

There are six ways:

  1. the vertices of a square
  2. the vertices of a 60-degree rhombus
  3. the vertices of an equlateral triangle, plus its midpoint
  4. the vertices of an equlateral triangle, plus a point on a symmetry axis that is a side-length away from the vertex through which that axis passes
  5. the vertices of an equlateral triangle, plus a point on a symmetry axis that is a side-length away, in the opposite direction, from the vertex through which that axis passes
  6. Four of the vertices of a regular pentagon