Difference between revisions of "AoPS Wiki talk:Problem of the Day/June 5, 2011"
(→Solution) |
|||
Line 4: | Line 4: | ||
{{potd_solution}} | {{potd_solution}} | ||
− | First, let's simply the expression <math> f(x) =\frac{x}{2}-\frac{5}{2} </math>. We have <math>f(g(7+-3)+3) = f(g(4)+3) | + | First, let's simply the expression <math> f(x) =\frac{x}{2}-\frac{5}{2} </math>. We have <math>f(g(7+-3)+3) = f(g(4)+3).</math> We know that <math>g(x)=4x-6</math>. |
− | + | That implies that <math>g(4)=4(4)-6=10</math>. Now we know that <math>f(g(7+-3)+3) = f(10+3) = f(13) = \frac{13}{2} - \frac{5}{2} = \boxed{4}</math>. |
Revision as of 21:41, 4 June 2011
Problem
AoPSWiki:Problem of the Day/June 5, 2011
Solution
This Problem of the Day needs a solution. If you have a solution for it, please help us out by adding it.
First, let's simply the expression . We have We know that .
That implies that . Now we know that .