Difference between revisions of "AoPS Wiki talk:Problem of the Day/July 3, 2011"
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==Solution== | ==Solution== | ||
− | { | + | If <math>x</math> and <math>y</math> vary inversely, then <math>xy = k</math> where <math>k</math> is a constant. We are given <math>x = 5</math> and <math>y = 8</math>, so <math>k = 40</math>. Now, we want to find <math>x</math> when <math>y = 10</math>, so we divide <math>40</math> by <math>10</math> to get <math>\boxed{4}</math>. |
Latest revision as of 10:18, 3 July 2011
Problem
AoPSWiki:Problem of the Day/July 3, 2011
Solution
If and vary inversely, then where is a constant. We are given and , so . Now, we want to find when , so we divide by to get .