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Difference between revisions of "1994 AJHSME Problems/Problem 13"

(Created page with "==Problem== The number halfway between <math>\dfrac{1}{6}</math> and <math>\dfrac{1}{4}</math> is <math>\text{(A)}\ \dfrac{1}{10} \qquad \text{(B)}\ \dfrac{1}{5} \qquad \text{(...")
(No difference)

Revision as of 14:40, 15 August 2011

Problem

The number halfway between $\dfrac{1}{6}$ and $\dfrac{1}{4}$ is

$\text{(A)}\ \dfrac{1}{10} \qquad \text{(B)}\ \dfrac{1}{5} \qquad \text{(C)}\ \dfrac{5}{24} \qquad \text{(D)}\ \dfrac{7}{24} \qquad \text{(E)}\ \dfrac{5}{12}$

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